IIT JEE , AIEEE Forum - Mathematics , Algebra

priyatamau

find the rationalising factor of ^[3]

25+^[3]

5+1 is

and also show that how can we find the period of sin(x⁰+2x⁰+ 3x⁰+4x⁰) is

yahiyafirdous

Let x=5^1/3

Hence given expression= x²+x+1

=(x-1)(x²+x+1)/(x-1)= (x³-1)/(x-1)

=4/(5^1/3-1) Ans

pink_ele

it is simple

(51/3-1) is the ans

as (51/3-1)(^3] 25+^[3] 5+1)=5-1=4

please make 2nd one clear

Asmita

I didn't understand d 2nd ques. properly..... But if we r asked 2 find period of that sine func. then it'll b = 2

=360⁰

yahiyafirdous

Put any known value of sin(10x⁰) say 0 and then find corresponding two consecutive values of x, difference of coressponding consecutive value of x is required.

sin(10x⁰)=0

10x⁰=2n, put n=0, 1

Hence required period is x=36⁰ Ans

_{[ ]}

iitkgp_bipin

25^1/3 + 5^1/3 + 1 = 5^2/3 + 5^1/3 + 1 which is in the form of x² + x + 1

Hence its rationalizing factor would be (x-1) which when multiplied by x² + x + 1 gives x³ - 1.

Hence rationalizing factor = 5^1/3 - 1

Please post your other query on a new page.

Ask & Discuss Questions with Community & Experts