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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2007 20:55:30 IST
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If a,b,c,d are distinct integers in AP such that d=a2 +b2 +c2 then a+b+c+d=? Plzz helpp
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-Ramya |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2007 21:50:35 IST
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experts plzz help
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-Ramya |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2007 21:59:00 IST
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wat do you mean by d=a2+b2+c2+d2 Do you mean "d" in the LHS is the common difference?
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SOME SAY SKY IS THE LIMIT BUT TO ME
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Mar 2007 22:21:36 IST
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How can d be equal to a^2+b^2+c^2+d^2???
d<=d^2
Also a, b, c (sqrd) > 0
(coz they r in AP)
Cant understand the question...
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"If you win, you shall not have to explain and if you lose, you wont be there to explain"
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2007 01:04:07 IST
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here,d is not the common difference, as mentioned in the question, a,b,c,d are in AP, its the term in AP, u can consider common dff. as some x. And sorry, made a mistake in the question, it is actually d= a^2+b^2+c^2 , i'll correct it.
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-Ramya |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2007 10:17:04 IST
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Hi a+b+c+d = 4 /2 ( a+d) = 2(a+d) Using the formula for summation of A.p 2(a+d) = 2(a+a2+b2+c2) as its given d = a2+b2+c2 Hence a+b+c+d = 2(a+a2+b2+c2) This is just the direct application of properties of A.P. I dont know in what way the answer is expected ie The sum should be in what terms. So I just tried it in the above way. Please tell me if I am wrong. Cheers!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2007 10:50:05 IST
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let a=A-3D b=A-D c=A+D d=A+3D
d=a2+b2+c2
assuming like this U can do it
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ARUN
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2007 16:46:19 IST
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well, the answer given is 2, newayz, thanks kiran
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-Ramya |
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