IIT JEE , AIEEE Forum - Mathematics , Algebra

vivekanand447

Find the sum to n terms 1+2*2+3*3*3+4*4*4*4+....................

amar.gupta

Dear,

it is not always possible to get a sum of series. however i will give u a general method to get the ans.

let 1+2*2+3*3*3+4*4*4*4+....................+n^n=A+Bn+Cn^2+Dn^3+............

where A,B,C,D,.....................are independant of n

replace n with (n+1) in above and substract with the above :

(n+1)^n-n^n=B+C(2n+1)+D(3n^2+3n+1)....................

this relation is true for every n just compare the coefficient of same powers of n you will get the eq. in A,B,C.............

solve it and you get the ans.