sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

 Moderation Team
 90 chars left    advanced
Ask iit jee aieee pet cbse icse state board community Community Discussion Question: progression
Forum Index -> Algebra like the article? email it to a friend.  
Author Message
[Post New]28 Feb 2007 15:57:23 IST
    Subject: progression
[Up] View Post
ishan (0)

New kid on the Block

Olaaa!! Perrrfect answer. 0  [0 rates]
ishan's Avatar
total posts: 17    
offline Offline
sum 2 infinity
(3/1^3)+(5/1^3+2^3)+(7/1^3+2^3+3^3)+......
a)3 b)4 c)5 d)6
 
 
 
 
 
 
 
 
 
 
 
    
[Post New]28 Feb 2007 17:06:24 IST
    Subject: Re:progression
[Up] View Post
vinu (524)

Blazing goIITian

Olaaa!! Perrrfect answer. 78  bad job dude!! I dont approve of this answer! 1  [147 rates]
vinu's Avatar
total posts: 318    
offline Offline
Hi ishan,
The rth term is.....(2r+1) / (13+23+...r3) ;
= 4(2r+1) / { r2(r+1)2 }  ;
= 4 { 1/r2 - 1/(r+1)2 } ;
 
[r=1][n] (2r+1) / (13+23+...r3) = 4{1 - 1/(n+1)2 } ;
                                          = 4 {as n->infinity }.
Option b)'s the ans.
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
 
Forum Index -> Algebra
Go to:   

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya