IIT JEE , AIEEE Forum - Mathematics , Algebra

ankitasingh

sum to n terms of:

1+1/2^2 + 1/3^2 +........

vivek54761

the summation of ur specified term upto infinity is {[pie]^2} divided by 6

ankitasingh

what about sum, 2 n terms? n cn u plz explain how is sum 2 infinity pie^2 /6?

vivek54761

madam i think 99% this is a wrong question.
plzz tell the complete question.

for_succes

it is a H.P. series..

and the formula to find:

The sum of the squares of "n" natural nos is n(n+1)(2n+1)/6

so, 1 + 2²+ 3² +.... = n(n+1)(2n+1)/6

And hence the answer is

6 / n ( n + 1 ) ( 2n + 1 )

Plz rate if thats rite....

rebel

hey i have another method--------------

integrate 1 / [xsqaure] from 1 to infinty !!

for_succes

but this is the easist fer objective and also subjective type coz time is of prime importance.......
cheeers

rebel

how can u say that for an hp the sum gets reversed with respect to an ap ??? any proof ??