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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Apr 2007 23:25:41 IST
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sum 2 n terms- 1+ 1/2 + 1/3 +.......+1/n
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14 Apr 2007 00:00:49 IST
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 Hey it is easy as a pie. Using G.p. 1+x+x2+x3+...............+xn-1 = xn-1-1 x-1 Now integrate both sides wrt x. then putx=1 solve to get answer. And rate if you get the ans.
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I cannot even solve 20% of the problem asked here. But each time i click i learn something new. GOIIT ROCKS ................................................................................................................................................. |
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14 Apr 2007 12:40:27 IST
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hey wat hav u done just check the ans.it is hp not gp
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adversities cause some men to break other to break records............i m of the other type....... :-) |
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14 Apr 2007 12:41:15 IST
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ans. is n/(n+1)
if that is so i will post sol.
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adversities cause some men to break other to break records............i m of the other type....... :-) |
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14 Apr 2007 17:24:59 IST
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guys,
A HP CANNOT BE SUMMED,the ques. thus is incorrect.i had the same query few months a go.CHEERS
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IIT- Imposible Is This(atleast fr meeeeeeeee) |
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14 Apr 2007 19:14:18 IST
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What Nick said, is right. Given series is an H.P. and hence it cannot be summed.
And Ankur.... How did you get it as n/(n + 1) ??!!
Put n = 2, and you won't get it as 3/2, instead 2/3.....
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14 Apr 2007 23:13:42 IST
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no its not the topic to be put under progressions i think if the ans is 'logN' i can give u the pross
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two imp facts abt me.................
1)NIGITHA REDDY is never wrong
2)if u feel that i am wrong in any case then...............slap urself n read the 1st fact properly!!!!!!!!!!! |
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15 Apr 2007 00:13:51 IST
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The series cannot be summed. In any case, it is divergent.
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15 Apr 2007 12:00:40 IST
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ankur u better post the solution
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15 Apr 2007 15:44:19 IST
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sorry i was confused
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adversities cause some men to break other to break records............i m of the other type....... :-) |
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15 Apr 2007 20:03:46 IST
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hp sereis cannot be summed that easily, we must use the integral method(using lowwer &upper bound values) which tells us that value of the series is in between
1+ln n& ln (n+1)
this can be approximately taken as ln n.
so the answer is close to ln n.
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