IIT JEE , AIEEE Forum - Mathematics , Algebra

shobhita

the AM of two nos exceeds their GM by 2 and the GM exceeds their HM by 8/5,find the nos.

asagwal

gm^2= am*hm
which gives gm=8
and am=10
solving we get nos. r 4,16
please rate if u r satisfied(ask me again if u r not)

asagwal

reply

swaroopcool21

the 2 nos are 16 & 4

assume 2 nos to be a & b

we get 1st equa.

(a+b)/2 -

ab = 2

2nd equa.

ab - 2ab/(a+b) = 8/5

put a+b = x

^ab=y

solving these qua.

x/2 - y = 2 ..................(1)

y - [(2y²)/x] = 8/5 ......................(2)

we get x=20 ; y=8

again solving,

x= a+b = 20

y=

ab = 8

we get

a=16 or a=4

b=4 or b=16

implies the required nos. are {16 , 4}

don't forget to rate me

shobhita

thanks alot to both of above