| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Nov 2007 21:01:23 IST
|
|
|
Find [n ] [infinity ] ( 1/n^100)( [ 1] [ n] r^99) Anyone?
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
    
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE> |
|
|
|
|
|
|
|
1/n sigma (r/n)^99
since its represented as a function of r/n inside sigma and there's 1/n outside...we can use limit as sum formula....
integrate x^99
upper limit = lim n->inf (1/n) =0
lower limit = lim n->inf (n/n) =1
so answer should be 1/100.
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Nov 2007 21:47:10 IST
|
|
|
gee thanks! i never thought of doing it by that method!
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE> |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Nov 2007 21:48:48 IST
|
|
|
my pleasure buddy!
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Nov 2007 21:52:08 IST
|
|
|
And hey by the way, can this be done by the progressions method.
like we have sigma n^2 and sigma n^3, do we have a general formula for say sigma n^r ?
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE> |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Nov 2007 21:54:59 IST
|
|
|
may be there is....but i don't know....
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Nov 2007 21:57:16 IST
|
|
|
ok then never mind.....i dont think there may be one coz even at sigma n^3 things start to get complicated so perhaps there may not be any generalization...anyways thanks again!
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE> |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
