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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 May 2008 22:03:12 IST
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a bag contains 10W balls & 15 B balls. 4 balls r drawn frm d bag let l,m,n respectively denote d probabilities dat d selection contains atleast 2 black balls at least 1 white ball at most 3 white balls & 2 black balls den
1. l>m>n
2. m>l>n
3. m<n<l
4. n>l>m
A 3 digit no. is chosen at random den d probability dat it is divisible by 9 given dat it is divisible by 11is
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21 May 2008 22:32:46 IST
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the first 3digit no. divisible by 99 is 198 and the last is 990 so there are 8 terms
the first 3 digit no. divisible by 11 is 110 and the last is 990 so there are 80 terms so ans is 1/10
the second q is not clear i mean there r only 3 terms l,m,n but the wordings i am not able to understand.can u
give the 3 events
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21 May 2008 23:24:50 IST
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for the first ques u have given 3 probabilities l m n but in the conditions thr r 4 given.....plzzz clarify
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21 May 2008 23:46:34 IST
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dats wat d problem i also face i didnot un derstand d question can ne 1 clarify that
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22 May 2008 17:30:47 IST
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The answer for the question is l>m>n
First let us calculate the probabilities:
l is the probability of getting at least 2 black balls therefore the probability is (15c2+15c3+15c4)/25c4
m is the probability of getting atleast 1 white ball therefore the probability is (10c1+10c2+10c3+10c4)/25c4
n is the probability of getting atmost 3 white balls and 2 black balls, there are two conditions in this, the first condition means that we have to get maximum of 3 white balls in the drawn 4 balls and the second condition means that there should 2 black balls in the drawn 4 balls, therefore the probability is (10c1+10c2)/25c4
Since the denominator is common the we will make the relation considering the numerator.
l=1925/25c4
m=385/25c4
n=55/25c4
Therefore the relation l>m>n is correct.
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22 May 2008 17:53:41 IST
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I think the ans is l>m>n but there is a mistake in the above calculations,The values of l,m,n are
l(25c4)=15c2.10c2+15c3.10c1+15c4
m(25c4)=10c1.15c3+10c2.15c2+10c3.15c1+10c4
n(25c4)=10c2.15c2+10c3.15c1
By calculating their values,we observe that l>m>n
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22 May 2008 20:58:39 IST
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I missed the calculation logic.
Thanks for correcting me Allamraju!
Yes we should multiply the mutually exclusive events
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23 May 2008 21:32:49 IST
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sorry allamragu & hpudipeddi d answer is 2nd option can u give me d solution
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23 May 2008 22:10:23 IST
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Sorry i have done a silly mistake
Favourable situations for
L-2B-2W
3B-1W
4B-0W
M-3B-1W
2B-2W
1B-3W
0B-4W
N-1W-3B(For furthur understanding of N see the ending part)
2W-2B
By a simple understanding:
L has 3 combinations favourable
M has 4 combinations favourable
N has 2 combinations favourable
Even without the actual calculation of the probabilities we can conclude that the relation m>l>n.
For N is the probability of getting atmost 3 white balls and 2 black balls there are 2 conditions in this, the first condition means that it there should maximim of 3 white balls and the second condition means that there should be atleast 2 black balls.
I think this will do it.
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23 May 2008 22:11:48 IST
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Sorry i have done a calculation mistake
Favourable situations for
L-2B-2W
3B-1W
4B-0W
M-3B-1W
2B-2W
1B-3W
0B-4W
N-1W-3B(For furthur understanding of N see the ending part)
2W-2B
By a simple understanding:
L has 3 combinations favourable
M has 4 combinations favourable
N has 2 combinations favourable
Even without the actual calculation of the probabilities we can conclude that the relation m>l>n.By calculation also we will get the same answer
For N is the probability of getting atmost 3 white balls and 2 black balls there are 2 conditions in this, the first condition means that it there should maximim of 3 white balls and the second condition means that there should be atleast 2 black balls.
I think this will do it.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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23 May 2008 22:12:11 IST
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Sorry i have done a calculation mistake
Favourable situations for
L-2B-2W
3B-1W
4B-0W
M-3B-1W
2B-2W
1B-3W
0B-4W
N-1W-3B(For furthur understanding of N see the ending part)
2W-2B
By a simple understanding:
L has 3 combinations favourable
M has 4 combinations favourable
N has 2 combinations favourable
Even without the actual calculation of the probabilities we can conclude that the relation m>l>n.By calculation also we will get the same answer
For N is the probability of getting atmost 3 white balls and 2 black balls there are 2 conditions in this, the first condition means that it there should maximim of 3 white balls and the second condition means that there should be atleast 2 black balls.
I think this will do it.
Rate if Helpful
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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24 May 2008 09:37:38 IST
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Oh...Amulye,My answer is correct.I just didnot calculate the values of l,m,n correctly,I made a calculation mistake.If you calculate the values which I have given,U observe that m>l>n.Sorry for the mistake.
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