|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Jan 2007 22:59:38 IST
|
|
|
There are 6n tickets numbered 0,1,2........., 6n-1 placed in a bag & three of the tickets are drwan out. Show that the probability for the sum of the numbers on the tickets to be 6n is 3n / [ (6n-1)(6n-2) ] Puneet Bhaiya, plz solve the above problem. I will be eagerly waiting for your reply. 
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Jan 2007 11:32:30 IST
|
|
|
Puneet sir, I'm waiting for your reply
|
You never know what is enough till you know what is more than enough.
Titun |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
yaaaaar question to chil hi hai .. answer galta lag raha hai .. favorable case mein to bas find the coeff of 6n in ( 1 + x + x^2 + ... + x^(6n-1) )^3 And total case are 6n choose 3 .. rite par answer to ye nai aaega usese just check it out . ?? cheers
|
Puneet Agrawal
IIT Delhi
|
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|