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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jan 2007 12:54:01 IST
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for a sequence, whose a1= 1/3 and an+1 = an + (an )2 , find the greatest integer velue of the sum given by [ r=2] [ 2008] (1/ a r ) Bhaiya, is the answer 1 for this,,, pls reply asap......
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Manasi....
NIT-Allahabad...
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Challenges are High, Dreams r New..
The World out thr is waiting for U !!
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i tried to solve the question but got only an inequality
i am not sure how to calculate the full answer
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28 Jan 2007 22:11:05 IST
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can you tell me your approach
i had changed the parameters
a(n) means nth term
let t n=1/a n
so t1=3
and also t(n+1)=t(n)^2/(t(n)+1)
t(n+1)=t(n)-1+1/(t(n)+1)
now to the sum add and substract t(1)
(t(2)+t(3)+..........+t(n)) where n=2008
the terms as we go on keep decreasing from 9/4
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28 Jan 2007 22:11:25 IST
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this one just came in todays fiitjee aits.....
check the solution...its quite easy
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28 Jan 2007 22:18:21 IST
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28 Jan 2007 22:19:36 IST
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yeah it was in fiitjee's aits, in paper1, n i had asked it to experts, in noon only, hoping to knw then only, if i hav done right or wrong, newayz i hav got a solution now, so no need of solving.....
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Manasi....
NIT-Allahabad...
............................................................
Challenges are High, Dreams r New..
The World out thr is waiting for U !!
Dare to dream, Dare to Try..
No Goal is distant, no Star is too high !!! |
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28 Jan 2007 22:22:27 IST
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well magicklo, can i know ur score for the last test full test-3...what percentiles do u usually get?
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28 Jan 2007 22:24:50 IST
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urs 1st pls, i knw they'll be gud ones 
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Manasi....
NIT-Allahabad...
............................................................
Challenges are High, Dreams r New..
The World out thr is waiting for U !!
Dare to dream, Dare to Try..
No Goal is distant, no Star is too high !!! |
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28 Jan 2007 22:26:49 IST
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well ain't that gud, paper 1 98(total) paper 2 117....adding up to 215..tht's almost like the highest i ever got...wht abt urs?
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28 Jan 2007 22:30:09 IST
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more or less same, 97in 1st, and 137 in 2nd, adding to 234, n its best ever frm me too....
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Manasi....
NIT-Allahabad...
............................................................
Challenges are High, Dreams r New..
The World out thr is waiting for U !!
Dare to dream, Dare to Try..
No Goal is distant, no Star is too high !!! |
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28 Jan 2007 22:51:42 IST
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hmmm............
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i am the genius....... |
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28 Jan 2007 22:54:40 IST
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wat is meant by "hmmm"???
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Manasi....
NIT-Allahabad...
............................................................
Challenges are High, Dreams r New..
The World out thr is waiting for U !!
Dare to dream, Dare to Try..
No Goal is distant, no Star is too high !!! |
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28 Jan 2007 22:55:09 IST
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hii magiclo ... gr8 that u have got the solution .. I was just wondering of u cud put up the solution for the benefit of many others on this community .. I hope u do not mind that ... cheers
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Puneet Agrawal
IIT Delhi
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29 Jan 2007 20:46:27 IST
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bhaiya, m srry, i hva realised it now, the solution given is wrong, so if u could give me the solution i'll be gr8ful, wat they hav given as the solution is as follows, Since an+1 = an (1 + an) Then 1/ar = 1/ [ar (ar+1) ] = 1/ ar - 1/ (ar+1) Now S = [1/ a1 - 1/ (a2)] + [1/ a2 - 1/ (a3) ] + [1/ a3 - 1/ (a4) ]+ .......... =1/ a1 - 1/ a2008 thrfore [S]=2 this is wat they hav given, i hav copied it totally word by word, but isnt it wrong (the bold one)...so i wish if u cud give the right solution,( provided it has got any solution, cuz i dnt think, it has)
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Manasi....
NIT-Allahabad...
............................................................
Challenges are High, Dreams r New..
The World out thr is waiting for U !!
Dare to dream, Dare to Try..
No Goal is distant, no Star is too high !!! |
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