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dixit_se (0)

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solve
___x-1______   <1
x2-4x+3

    
nivedh_89 (4573)

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(x-1)/(x-3)(x-1)<1

therefore
1/(x-3)<1
hence
x-3>1
x>4................!!!!!!!!!!!!
 oh  yes........
x<4 but x {1,3}

The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....

the PAIN or the PERSON...!!!
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metal (491)

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Hey,
       nivedh you are wrong. (x-3) can be greater than zero or less than it, there are two possibilities.
If x-1=0 , then the inequality holds true and x=1. Else
if x-1 is not equal to zero,
x2-4x+3=(x-1)(x-3) and the (x-1) in the numerator and denominator cancel each other.
So, weget 1/(x-3) < 1.          [ineq 1]
Now, if x-3>=0 i.e. x>=3,
from [ineq 1] we get x-3>1, i.e. x>4.
combining both we get x>4.
Again if x-3<0, i.e. x<3 ,
from [ineq 1] we get x-3<1 i.e. x<4.
combining both we get x<4.
So the answer is (x<4)U(x=1)U(x>4)
 
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nivedh_89 (4573)

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x cannot b equal 2 1 nor can it b equal 2 3................!!!!!!!!!!!

The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....

the PAIN or the PERSON...!!!
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sankydreams (1005)

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1/(x-3)<1
1/(x-3) - 1 < 0
(4 - x) / (x-3)<0
(x - 4) / ( x-3) > 0
Now apply wavy curve method and get ans as (-infinity,3)U(4,infinty)
rate if this helps u...


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rini (221)

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the ans should be ..

x= R - (3,4) - {1}

Keep working....................Iam comming..

your's only,
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metal (491)

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Nivedh, why can't x be 1?
put x=1.
the numerator becomes zero.
So,the whole L.H.S becomes zero, which is obviously less than 1.
Got it????????!!!!!!!.
 
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spideyunlimited (4185)

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(x-1) / (x-3)(x-1)
1/(x-3)<1                 provided x not = 1 we have cancelled out (x-1)
1/(x-3) - 1 < 0
(4 - x) / (x-3)<0
(x - 4) / ( x-3) > 0

x E (-inf, 3) U (4, +inf) ~ {1}

*PLZ RATE*

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- Gaurav Ragtah (spideyunlimited)
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spideyunlimited (4185)

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metal!!!!!! u cant put x = 1... u will get 0 in denominator also... not defined buddy

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- Gaurav Ragtah (spideyunlimited)
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akku (1142)

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ans: x (- ,3)(4,)-{1}
soln:
bringing 1 2 the LHS
-X^2+5X-4/(X-1)(X-3)<0
MULIPLY BY - AND REVERSE SIGN OF INEQUALITY
(X^2-5X+4)/(X-1)(X-3)>0
(X-1)(X-4)/(X-1)(X-3)>0
X  is NOT = 1 as fn will b undefined
(x-3)(x-4)>0
x belongs to (-inf , 3) U(4, inf)-{1}
P.S. X is same as x(pls dont mind the capital fonts)
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metal (491)

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Got it, spidey,x is not = 1.
Then the correct answer is (-infinity,4)U(4,infinity)
 
please rate.
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shohitaa (274)

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see on factorising we get

(x-1)/(x-1)(x-3)<1

so we get (1/(x-3))-1<0

on solving:
(4-x)/(x-3)<0

taking -1 common we get
x-4/x-3>0
so finally we get
by wavy curve method

x belongs to (-inf,3)U(4, inf)

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spideyunlimited (4185)

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metal!!! it is (-inf, 3) U (4, +inf) ~ {1}

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- Gaurav Ragtah (spideyunlimited)
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