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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Oct 2007 15:01:14 IST
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Rates assured, plz solve : 1) Show that no real values of x and y other than 4 and 4 respectively will satisfy the eqn x2 - xy + y2 = 4(x + y - 4). 2) Find 'a' for which x2 - x + a - 3 < 0 for aleast one negative x. Plz give detailed solutions...
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Put your hand on a stove for a minute and it seems like an hour. Sit with that special girl for an hour and it seems like a minute. That's relativity.
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And it's now or never
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-Anonymous |
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17 Oct 2007 21:06:40 IST
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waiting,plz reply...
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Put your hand on a stove for a minute and it seems like an hour. Sit with that special girl for an hour and it seems like a minute. That's relativity.
-Albert Einstein
Generally people who take the piss out of other people hang around in groups of five, because they have a fifth of a personality each.
- Eddie Izzard
It's my life
And it's now or never
I ain't gonna live forever
I just wanna live while I'm alive
-Bon Jovi
By the time a son realizes that his father was probably right, he has a son who thinks he is wrong.
-Anonymous |
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17 Oct 2007 21:07:14 IST
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Q-1
rewrite as ---- x^2 - (y+4)x+ y^2 - 4y + 16=0
D=(y+4)^2 - 4(y^2 - 4y + 16)
=-3(y-4)^2
now D>=0
or -3(y-4)^2>=0 hence y=4
similarly x=4
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17 Oct 2007 21:22:01 IST
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Q-2
above funcion(F) is decreacing in -infinty to 1/2
hence F(x)>F(0) for x less than 0
hence if F has to be <0 for any -ve x then F(0) has to be < 0
we get a-3<0
or a<3
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