| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 May 2007 14:59:13 IST
|
|
|
If  , where [x] is the greatest integer less than or equal to x, then the number of solutions of  are : |
adversities cause some men to break other to break records............i m of the other type....... :-) |
|
|
|
31 May 2007 15:17:49 IST
|
|
|
is the ans 1 reply me if i'm crt
|
navi009 is always there to help u!!!!!!!!!!
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
31 May 2007 15:19:00 IST
|
|
|
commonnnnnnnnnnnnnn!!!!!!!!!!
|
navi009 is always there to help u!!!!!!!!!!
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
31 May 2007 15:27:38 IST
|
|
|
f(x)+ f(1/x) =x-[x] + 1/x-[1/x] = x-[x] + 1/x =1 in this eqn i've found that only 1 is satisfying plz tell me if i'm crt!!!!!!!!!!!
|
navi009 is always there to help u!!!!!!!!!!
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
31 May 2007 16:22:16 IST
|
|
|
|
Keep working....................Iam comming..
your's only,
Success!! |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
31 May 2007 16:23:41 IST
|
|
|
the equation here shows that you need to take 4 conditions
x< -1, -1<=x<0, 0
atx<-1
[x]=x-1
[(1/x)]=-1
x-(x-1) - {f} +1=1 where{f}=fractional part
1-{f}=0
but 0<{f}<1
hence not applicable
at -1<=x<0
[x]=-1
[(1/x)]= -ve Integer
x-(-1) + negative no-it's greatest integer=1
x+1+{f}=1
x=negative of fractional part
hence there are infinite solutions
|
akash |
this reply: 10 points
(with 2
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
31 May 2007 17:03:38 IST
|
|
|
correct
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
31 May 2007 18:35:40 IST
|
|
|
f(x)+ f(1/x) = 1 => x-[x] + 1/x-[1/x] = 1
=> x + 1/x = 1+ [x] + [1/x] now RHS has to be an integer....that means LHS is also an integer.....which is possible only if x =1
|
Manasi....
NIT-Allahabad...
............................................................
Challenges are High, Dreams r New..
The World out thr is waiting for U !!
Dare to dream, Dare to Try..
No Goal is distant, no Star is too high !!! |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
31 May 2007 18:45:28 IST
|
|
|
the answer is infinite .
but funky can u elaborate ur last line
|
adversities cause some men to break other to break records............i m of the other type....... :-) |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
1 Jun 2007 15:20:08 IST
|
|
|
what I want to say is that when x lies between -1and 0, the value of x comes out to be -{f}.
this means that x takes all real values between -1 to 0 which is a fractional part.eg: it will take values like,-0.01 ,-0.002,-0.45 etc hence there are infinite solutions.
|
akash |
this reply: 15 points
(with 3
in 3 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
1
