| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 16:37:37 IST
|
|
|
q) Find the condition on a,b,c,d for which 2ax3 + bx2 + cx + d = 0 and 2ax2 + 3bx + 4c = 0 have a common root.
|
There is no better feeling in this world than being a winner! |
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 16:44:27 IST
|
|
|
are a,b,c.d in a.p...?? nt sure though.....
|
see da "letter to santa" in ma album ...!!! |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:24:20 IST
|
|
|
don't know the answer..plz post the soln!
|
There is no better feeling in this world than being a winner! |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:29:29 IST
|
|
|
pata nahi... kabhi aisa question kiya nahi
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:32:41 IST
|
|
|
see the next post
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:35:02 IST
|
|
|
nice qns , but idea at all!
|
>>sugeet->
--catalysingsuccess |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:41:36 IST
|
|
|
the next post
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:42:31 IST
|
|
|
ashish u post it na... i want to know how u proceeded ?
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:48:52 IST
|
|
|
let z be the common root then 2az3 + b z2 + cz + d =0 ...............1 and 2az2 + 3bz + 4c = 0........................2 equation 1 is z( 2az2 + bz + c) +d = 0 replace the value of 2az2 from second and replace in 1 2bz2 + 3cz - d =0.......................3 now z is the common root of 2 and 3 its easy afterwards
|
this reply: 7 points
(with 1 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:55:31 IST
|
|
|
please check
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 17:57:53 IST
|
|
|
i think u r rite... but u dont hav options na nahi to confirm ho jata...
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|