Algebra

Cool goIITian

Joined: 21 Mar 2012
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2 Apr 2012 22:14:59 IST
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quadratic equation
Engineering Entrance , JEE Main , JEE Main & Advanced , Mathematics , Algebra

Solve the equationx|x+1 |+ a=0 for every real number 'a'



Comments (9)


Blazing goIITian

Joined: 21 Mar 2012
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2 Apr 2012 22:18:07 IST
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options

Blazing goIITian

Joined: 21 Mar 2012
Posts: 1457
2 Apr 2012 22:19:07 IST
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i think x=-1+_a

Cool goIITian

Joined: 21 Mar 2012
Posts: 37
2 Apr 2012 22:28:55 IST
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 answer is  x={-1/2-(1-4a)^1/2/2 for all a<=1/4  ,  -1/2-(1-4a))^1/2/2 for 0<=a<=1/4


Cool goIITian

Joined: 21 Mar 2012
Posts: 37
2 Apr 2012 22:30:10 IST
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please anyone suggest me the method to solve this

 


Blazing goIITian

Joined: 21 Mar 2012
Posts: 1457
2 Apr 2012 22:39:35 IST
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what is differnce btw, the two

Blazing goIITian

Joined: 21 Mar 2012
Posts: 1457
2 Apr 2012 22:40:10 IST
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i think its from rd sharma

Blazing goIITian

Joined: 21 Mar 2012
Posts: 1457
2 Apr 2012 22:52:00 IST
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i can provide u full proof solution so tht u can belirve me

Blazing goIITian

Joined: 21 Mar 2012
Posts: 1457
2 Apr 2012 23:03:12 IST
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and yes a cant be positive ever due to /x+1/=-a and modulus function always gives +ve value so a cant be >0 but in answer a>0 what a joke lolzzzzzzzzz

Cool goIITian

Joined: 29 Mar 2012
Posts: 62
5 Apr 2012 12:22:47 IST
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 See easy one.but a very important concept.

   is a modulus fn. x can be negative or a positive value.therefore we have three situations.

1 when x.>-1

then the modulus becomes positive and we have.

x+1+a=0

thereforea=-(x+1)

2.when x=-1

a=0

3.when x<-1

mod opens and term is neghatve.

a=x+1

please rate.

 




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