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Ask iit jee aieee pet cbse icse state board experts Expert Question: quadratic equations
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[Post New]4 Dec 2006 15:05:19 IST
    Subject: quadratic equations
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avik (0)

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solve for x
 
4 x + 1.5 + 9 x + 0.5 = 10 * ( 6 x )
    
[Post New]4 Dec 2006 17:06:49 IST
    Subject: Re:quadratic equations
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edison (4425)

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4 x + 1.5 + 9 x + 0.5 = 10 * ( 6 x )
 
or 4x 4 1.5 + 9x 90.5 = 10 * ( 6 x )
 
or 22x 8 + 3 2x 3= 10 * ( 3x 2x )
 
Let and 2x = u     and   3x = v
 
Therefore, above equation becomes as
 
8u2 +  3v2 = 10uv
 
or  8u2 - 10uv +  3v2   = 0
 
or  8u2 - 6uv - 4uv +  3v2   = 0
 
or 2u( 4u - 3v) - v( 4u - 3v) = 0
 
or ( 4u - 3v) ( 2u - v) = 0
 
or 4u = 3v   and  2u = v
 
or 4*2x = 3*3x   and 2*2x = 3x  
 
Now find the value of 'x'.
 
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