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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: ques. on binomial
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busyinstudies (27)

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what is the remainder left when  is divided by 1990???????????


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busyinstudies (27)

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it's easy atleast try.........

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busyinstudies (27)

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this is so easyyyy...........

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busyinstudies (27)

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no one can answer such a simple ques......

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Decoder (774)

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i am trying...does tht ques. exist ..cuz...i am not finding any bino. resemblance..

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busyinstudies (27)

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ya the solution exists....
n it's in my binomial questions

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man111 (54)

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Re:ques. on binomial
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man111 (54)

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IS it answer is 2..............................
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man111 (54)

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2 = (1+1)^n and expand it....
(1+1)^n = 1+(n,1)+(n,2)..................(n,n-1)+(n,n)
= 1+n*(...................)+1 (bcz value of (n,n) =1)
then divide this expression by n
means (1+1)^n / n = 2 +n*(..................)/n =2
2 is the remainder
put n = 1990 in this expression..........
(n,r) = denotes ncr values
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busyinstudies (27)

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no it's wrong

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busyinstudies (27)

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wat's the answer of this urs last solution

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hamba (429)

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this can be solved better using Number Theory, than Bionomial.




 


Answer is 1024.....try by Fermat's little theorem.




 


Hint :- 2199-2  is divisible by 199. nudge if not got answer...


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They who know how to know, know everything....
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man111 (54)

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(1) Integrate 1/sin(x-a)*sin(x-b) w.r.to x.


H.S.bhatt Sir is there is any different method to solve these type of question  (apart from cut and past)........

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Decoder (774)

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man111 ... saving nickels huh ?? :D:D...

i think u know tht method...multiplying sin(a-b) in both nr-dr.
tht's the fastest one i think...( tht's is cut & paste) :D:D

try by converting into exponential form(complex) approach..

or just ..wait for sir's reply..


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shefalisaxena (29)

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first u tell the correct ans.


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