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man111 (42)

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(1)prove that (72!/36!)-1 divisable by 73.
    
hsbhatt (3649)

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I think there is a mistake in the qn. Here's why:
 
72!/36! - 1 = (37*38*39*...*72) - 1 = (73-36)*(73-35)*...*(73-1) = 73*k + 36! - 1.
 
It remains to prove that 36! - 1 is divisible by 73. This cannot be true from a property arising from Wilson's Theorem (Number Theory)  that if p is a prime then (p-1/2)! 2+1 is divisible by p if p is of the form 4k+1. Now 73 is such a prime, which gives (36!)2+1 is divisible by 73.
 
Now, if 36!-1 is div by 73 we must have from the above that 2.36! and hence 36!is also divisible by 73 i.e. 36!-1 and 36! are both div by 73 which is impossible.
 
 
 
 
 
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