From Fermat's "Little" Theorem, ap-1 is divisible by p if p is a prime and a is prime to p
Hence, for p = 5, a4 - 1 is divisible by 5. a4 is of the form 5k+1
Hence x4 + y4 leaves a remainder 2 when divided by 5 when x and y are not multiples of 5. 3789108 on the other hand leaves a remainder 3. You can similarly eliminate cases when x or y or both are multiples of 5.
Hence, there are no integral solutions.