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konichiwa2x (2224)

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No, not a challenge.. Can someone do this? Answer is 215 but my method runs into pages. surely, there has to be an easier method...so please try.

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nadeemoidu (1184)

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If u r ready to accept any other answer , I 'll give mine   . My answer is 5.
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amaron (726)

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The Problem isnt very difficult unless I am very much mistaken,


Let  a=(1+k) 1/3  and b =(k)1/3

Then the denominator reduces to  a2 + b2 + ab =( a3 - b3 )/(a-b)

But  a3 - b3     =   1

therefore substituting and by telescopic cancellation,

ans is 6 - 1 =5

That solves the problem!

Destiny is what you make


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arpan1 (665)

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even i am getting 5

all the best ...
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sandeepramesh (1245)

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nice one nadeem and amaron :)
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konichiwa2x (2224)

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  very nice amaron! thanks guys!

Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm

JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
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konichiwa2x (2224)

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cant beleive i actually messed up on that one Wallbash Red

Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm

JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
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