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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:35:38 IST
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 . No, not a challenge.. Can someone do this? Answer is 215 but my method runs into pages. surely, there has to be an easier method...so please try.
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:50:07 IST
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If u r ready to accept any other answer , I 'll give mine . My answer is 5.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:50:37 IST
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The Problem isnt very difficult unless I am very much mistaken,
Let a=(1+k) 1/3 and b =(k)1/3 Then the denominator reduces to a2 + b2 + ab =( a3 - b3 )/(a-b) But a3 - b3 = 1 therefore substituting and by telescopic cancellation, ans is 6 - 1 =5 That solves the problem!
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Destiny is what you make
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:54:22 IST
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even i am getting 5
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all the best ... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 21:58:30 IST
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nice one nadeem and amaron :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 22:12:51 IST
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very nice amaron! thanks guys!
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Mar 2008 22:24:12 IST
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cant beleive i actually messed up on that one
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
JEE and OLYMPIA INFINATUM
http://iit-redefined.theforum.name/index.php
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