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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 19:51:01 IST
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(1) if Z1,Z2,Z3 are in H.P(harmoni8c progression), then Z1,Z2,Z3 lies on
ans
parabola
stright line
circle.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 20:01:55 IST
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circle sir ji
very sure solve kiya hega
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 20:03:01 IST
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plz gave me full solution.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 20:10:26 IST
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pehle english sudharo apni
GAVE
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 20:12:26 IST
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aray bhaiyaa ans likh doo.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 20:13:18 IST
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but your ans is wrong exact ans is stright line.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 20:13:33 IST
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nice question...i think its a circle...cz as hp is inverse of ap.. the points keep on changing after an interval... sreee u were pretty rude if u dont mind..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 20:32:32 IST
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A circle passing thru origin
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 May 2008 11:15:10 IST
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Please see http://www.goiit.com/posts/list/trignometry-complex-numbers-40366.htm#198122
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Time wounds all heels |
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