(1) How can i solve this question numerically.

|x-2|-1

Simply write this function explicitly for the conditions x<2 and x>=2. plot the two solution sets on a number line and take the intersection.

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r u sure of the question....the q u have stated is true for all x..

|a|>=0 always

u have stated >=-1....equality is not possible but the inequaltiy always holds gud

For any modulus fx say |a|=a if a>0

                                               =0 if a=0

                                               =-a if a<0

so |a|>=0 always

since |x-2| is positive so

for all values of x |x-2| is zero or positive

so obviously infinite values of x can satisfy the relation

It cant be solve since its a rough identity

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