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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jan 2007 17:34:55 IST
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if alpha ,beta ,gamma,delta r the roots of the polynomial equation 1+x+x2+x3+x4=0 and alpha7,beta7,gamma7,delta7 are the roots of the 1+ax+bx2+cx3+dx4=0, then a+b+c+d=
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28 Jan 2007 18:53:14 IST
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hey i have a good solution for this
1+x+x2+x3+x4=0
(x^5-1)/(x-1)=0
here the roots are p,p^2,p^3,p^4
where p is the fifth root of unity
p^(5+n)=p^n
like we do in cube root of unity
using this property the roots will again become p^2,p^4,p,p^3
so the equation will become the same & a+b+c+d=4
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29 Jan 2007 17:18:50 IST
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great solution shakir even i was about to write the same solution 
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a 2nd year IIT DELHI student, doing B.Tech in chemical engineering |
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31 Jan 2007 19:56:13 IST
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thank u deepak and shakir
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