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man111 (42)

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(1) can anyone solve my question.
 
and there is no mistake in this question
prove that 72!/(36!)-1 is divisable by 73
 
this is the question which is given in arihant book interactive alzebra volume 2
level 3rd. 
    
konichiwa2x (2224)

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there IS a mistake in the question! it is not divisible by 73. (arihant IS known to be wrong at times.)
 
maybe the problem is to prove that is divisible by 73?

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hsbhatt (3278)

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I said earlier, there is a mistake in the prob bcos of this:
 
72!/36! - 1 = (37*38*39*...*72) - 1 = (73-36)*(73-35)*...*(73-1) = 73*k + 36! - 1.
 
It remains to prove that 36! - 1 is divisible by 73. This cannot be true from a property arising from Wilson's Theorem (Number Theory)  that if p is a prime then (p-1/2)! 2+1 is divisible by p if p is of the form 4k+1. Now 73 is such a prime, which gives (36!)2+1 is divisible by 73.
 
Now, if 36!-1 is div by 73 we must have from the above that 2.36! and hence 36!is also divisible by 73 i.e. 36!-1 and 36! are both div by 73 which is impossible.
 
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konichiwa2x (2224)

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ya exactly...
 
.

Notice also
 
it is quite clear, 73 doesnt figure in it...

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sboosy (2970)

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I had given a detailed answer when u asked with respect to 92! question
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