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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 22:13:52 IST
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from a panel of 5 lawyers , 5 chartered accountant and 1 lawyer who is also an charyered accountant ,how many committees of 4 can be made if each comimittee is to contain at least 1 lawyer and 1 chartered accoumtant
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 22:31:19 IST
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is it 11c4/2*5c4; i m not sure abt ans.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 22:35:35 IST
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ans = 320
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 22:37:26 IST
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oops
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 22:37:49 IST
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let 5 lawyers=A 5 CAs=B 1 lawyer/CA=C
to choose 4 possibilites are 3A 1B + 1A 3B= 2* 5C3*5C1=2*10*5=100 2A 2 B= 5C2*5C2=10*10=100
3A1C/3B 1 C= 2x5C3=20 2A 1B 1 C/2B 1A 1 C=2x5C2x5C1=100
so adding all these cases 320 possibilities
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 22:57:54 IST
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case 1 : person who is both lawyer & accountant is selected , then any three from the rest 10 can be selected so no .of ways = 10C3 = 120 case 2: the uniquely talented above person is not selected leaving three possibilites i) 2 lawyers & 2 accountants are selected , no .of ways = 5C2 * 5C2 = 100 ii) (3 lawyers and 1 accountant) or (1 lawyer & 3 accountants) = 2*5C3*5C1 = 100 so total ways = 120 + 200 = 320
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"Imagination is more important than knowledge."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 23:02:36 IST
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See this tabular form i have adopted to show this:
| No. of selections that can be made |
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| | 5 Lawyers | 3 | 2 | 1 | 2 | 1 | 3 | 0 |
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| | 3 CA's | 1 | 2 | 3 | 1 | 2 | 0 | 3 |
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| | 1 lawyer/CA | 0 | 0 | 0 | 1 | 1 | 1 | 1 | This states that in how many ways 4 people can be selected from the given people.
If u add all the 7 cases above u will surely get 320.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 23:10:37 IST
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See the working now, if u didn't get.
(5C3 x 5C1) + (5C2 x 5C2) + (5C1 x 5C3) + (5C2 x 5C1) + (5C1 x 5C2) + (5C3 + 5C3)= 50 + 100 + 50 + 50 + 50 + 10 + 10 =320
I haven't shown 5C0 and 1C1 in the working. I hope its useful and understandable.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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