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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Remainder
Forum Index -> Algebra like the article? email it to a friend.  
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[Post New]7 May 2008 20:38:07 IST
    Subject: Remainder
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donnowatnametochoose (34)

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The remainder when x=1! + 2! + 3! + 4!+ .....+ 100! is divided by 240 is
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[Post New]7 May 2008 20:39:18 IST
    Subject: Re:Remainder
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sandeepramesh (1245)

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153 :huh:huh:huh
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[Post New]7 May 2008 20:40:30 IST
    Subject: Re:Remainder
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donnowatnametochoose (34)

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Ya thats what is given but pl elaborate :)
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[Post New]7 May 2008 20:40:31 IST
    Subject: Remainder
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ashish_banga (927)

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153


 


240 = 2^4 X 3 X 5


these all the factors occur in 6 factorial


then the earlier terms add to remainder


remainder = 1 + 2 + 6 +24 + 120 = 153
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[Post New]7 May 2008 20:43:10 IST
    Subject: Re:Remainder
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sandeepramesh (1245)

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WTH? From 6! all are divisible by 240 so what? add the remaining nos no? :huh:huh:huh:huh:huh:huh:huh:huh
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[Post New]7 May 2008 20:44:25 IST
    Subject: Re:Remainder
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donnowatnametochoose (34)

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He he..was frustrated over not getting many answers thanks.
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