i = cos/2 + i sin/2 = ei/2 ii = (ei/2)i = e-/2 (As i2 = -1) = 1/e/2 Now e lies between 2 and 3. /2 is approximately = 1.57 Hence e/2 isn't a very large value. Infact it will be less than 6 but definitely greater than 1. Hence its reciprocal 1/e/2 should be less than unity And hence ii is a real number less than unity.
Please check the question. It shouldn't be a large real number.
Moderation Team
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-1=i & i^i=e^(-pi/2) . i is imaginary no. i^i which is imaginary raise to imaginary ,then how it is a very large real no. 
/2 + i sin
/2 = ei
