well...
go frm here
let m means be inserted
A1 , A2...........Am between 1 & 31 ok?
then 1 , A1 , A2...........Am , 31 are in AP
and u might be knowing this formula....d = (b-a) / n + 1
so common diff = 31 - 1 / m + 1= 30 / m + 1
now here the 7th term will nt b 1 + 6d....(as we have 2 more terms (1 and 31) )
so 7th term will be 1 + 7d = 1 + (7*30 / m + 1)
A7 = m + 211 / m + 1
Am-1 = 1 + (m-1)d = 1 + (30*(m-1) / m + 1) = 31m - 29 / m + 1
given the ratio of 7th to m-1 terms..hai na
so
jst put the values here
cross multiply
m comes out to be 14
if nt then tell me