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Algebra
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sandeep ramesh
Blazing goIITian

Joined: 13 Mar 2008
Posts: 1183
15 Mar 2008 14:17:34 IST
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telesopic sum only
make it n!(n+1)^2 - n!*n = (n+1)! * (n+1) - n!n = 100 * 100! - 1
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15 Mar 2008 15:31:17 IST
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this can be done in this way
n! (n2+n+1)
=n! ((n+1)2-n)
now keep on substituting values till 1 to 99
ie n=1---- 2*2! - 1*1!
n=2 + 3*3!- 2*2!
n=3 + 4*4!-3*3!
+ ............... and so on
n=98 + 99*99! - 98*98!
n=99 + 100*100!- 99*99!
all terms are cancelled except 100*100! - 1



99 n! ( n2 + n +1 ) is equal to ?












