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Algebra

Blazing goIITian

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Post:	598

5 May 2009 11:22:21 IST

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400

sequences and series 49

None

Suppose a,b,c are in AP and a²,b²,c² are in GP. If a<b<c and a+b+c = 3/2, then the value of a=?

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taran

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Joined: 17 Nov 2008

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5 May 2009 11:26:07 IST

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a= 1/2

Siddhant

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5 May 2009 11:40:21 IST

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rasham garg

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5 May 2009 11:48:11 IST

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let a,b,c be x-d,x,x+d a+b+c=3/2 3x=3/2 x=1/2

,b=1/2

1/4=[1/2-d][1/2+d]

d=0

a =1/2

student9_iit

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5 May 2009 12:23:34 IST

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a=1/2.

suppandi

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5 May 2009 21:31:04 IST

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no dude that is an obvious possibility, but its given a<b<c

NugoRama

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5 May 2009 21:36:56 IST

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a+b+c =3/2

a+c =2b

3b = 3/2

b = 1/2

a^2c^2 = b^4

a^2c^2 = 1/16

ac = 1/4

a + c =1

ac =1/4

c = 1/4a

a + 1/4a = 1

solvin quad ..gives a = 1/2 ..

contradicts the condition given..

hence no answer .

suppandi

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5 May 2009 21:52:20 IST

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answer is

Mirka

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5 May 2009 22:52:28 IST

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I have got d reqd. answer

NugoRama

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5 May 2009 22:53:11 IST

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thnx

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