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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2008 23:15:53 IST
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solve for x :- 3^log(a)x+3*x^log(a)3=2
()->base
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 08:24:14 IST
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note that k^log(a)x = x^log(a)k implies 4 * 3^log(a)x = 2 implies 3^log(a)x = 1/2 implies log(a)x = -log(3)2 implies x = a^{-log(3)2}
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 09:44:10 IST
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hey its wrong.................
the answer is 2^-log(3)a
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 09:55:03 IST
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as already pointed out by me 2^{-log(3)a} = a^{-log(3)2} By the rule i said before
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2008 16:37:53 IST
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hmmm........ thnx
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