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sourab_MCA (30)

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solve for x :-
3^log(a)x+3*x^log(a)3=2

()->base

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sandeepramesh (1247)

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note that k^log(a)x = x^log(a)k
 
implies 4 * 3^log(a)x = 2 implies 3^log(a)x = 1/2
implies log(a)x = -log(3)2
implies x = a^{-log(3)2}
 
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sourab_MCA (30)

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hey its wrong.................

the answer is 2^-log(3)a

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sandeepramesh (1247)

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as already pointed out by me 2^{-log(3)a} = a^{-log(3)2}
 
By the rule i said before
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sourab_MCA (30)

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hmmm........
thnx

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