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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 19:32:40 IST
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if x,y,z are positive real numbers such that x+y+z= 24, then find the greatest value of xy^2z^3.
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12 Aug 2007 19:52:37 IST
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This is me [avi], you never told me that you were joining goiit. Anyway, I will try finding the solution, and I will send it tomorrow. O.K.??????
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13 Aug 2007 23:13:57 IST
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I think the answer is 262144, will send thesoln if the answer is correct.
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I like to be myself. |
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13 Aug 2007 23:20:35 IST
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NO ! U R WRONG ! the answer is 442368.
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15 Aug 2007 12:38:06 IST
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(x+y/2+y/2+z/3+z/3+z/3)/6>=((xy^2z^3)/(4*27))^1/6
so, xy^2z^3<=4^6*4*27 = 442368
RATE ME BECAUSE I KNOW THIS IS CORRECT
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I like to be myself. |
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15 Aug 2007 12:58:07 IST
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I also know that Rajat's answer is correct, so you should also rate me....... [just joking]
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