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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Feb 2008 23:33:05 IST
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if 2a+3b+4c=5 then find the maximum value of a4b3c2 accha problem hai.....
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"Logic is the systematic way of reaching the wrong conclusion with confidence" lol..... |
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2 Feb 2008 00:35:42 IST
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edited
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2 Feb 2008 00:38:04 IST
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Answer is (5/9) 9 * 4
Is it correct??
Here goes my procedure
Since a4b3c2 is to be obtained
So we divide 2a,3b&4c into 4,3and2 parts consecutively...
So we have these numbers 2a/4,2a/4,2a/4,2a/4,b,b,b2c,2c
Now A.M = 2a/4+2a/4+2a/4+2a/4+b+b+b+2c+2c
4+3+2
= (2a+3b+4c)/9 = 5/9
Now considering G.M,
G.M = (2a/4*2a/4*2a/4*2a/4*b*b*b*2c*2c) 1/9
Applying
A.M  G.M
We have 5/9 (a4b3c2/4) 1/9
or a4b3c2  (5/9)9*4
So the maximum value a4b3c2 = (5/9)9 *4
I hope this is the answer...
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2 Feb 2008 08:38:03 IST
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Bingo....... well solved... i good problem isnt it...... problem from A.Dasgupta.....
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"Logic is the systematic way of reaching the wrong conclusion with confidence" lol..... |
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2 Feb 2008 12:05:02 IST
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good quest. and good ans... is this a pericular trick... good tool to solve thse problems i didnt know
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2 Feb 2008 19:03:32 IST
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Very gud skill of application show dude really u worth iit
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You Get what u really want |
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2 Feb 2008 19:25:54 IST
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excellent work greatdreams
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Will nip in at times to solve problems :)
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3 Feb 2008 16:50:24 IST
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well a.m  g.m is a general formula in the chapter sequence and series
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