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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jan 2007 17:18:18 IST
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1.the number of ways of distributing 6 identical appples ,8 identical bananas ,11 identical oranges between two boys so that each boy gets at least one fruit of each kind
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jan 2007 19:38:37 IST
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There are 6 identical apples,8 identical bananas,and 11 identival oranges.... So total no of ways of distributing apples among 2 students is 6p2... similarly for bananas and oranges the total no of ways is 8p2 and 11p2 respectively... So total no of ways of distributing it amongst the 2 persons is... 6p2+8p2+11p2.. Now by formulaof permutation NpR=N!/(N-R)! calculate each.. and find the answer.. by the way please answer my question... it seems that you are in 11th std... Thank you..
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AAKASH SRIVASTAVA
aakashaastha@rediffmail.com
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jan 2007 20:56:39 IST
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The ans is 25! / 6! 8! 11! - 2
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VAIBHAV BEST
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jan 2007 20:56:57 IST
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The ans is 25! / 6! 8! 11! - 2
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VAIBHAV BEST
< THE GAME IS ON > |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Jan 2007 09:31:16 IST
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(2^6)(2^8)(2^11)-(2^6-2^8-2^11)-(2^6)(2^8)-(2^8)(2^11)-(2^11)(2^6)........ see what i have done is total number of ways of distributing - ways of distributing so that none gets all the fruits each fruit can go to either of the 2 boys...so 2^n is ways of distributing n fruits among 2 boyz......think over it and llet me know any sort of prob
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a 2nd year IIT DELHI student, doing B.Tech in chemical engineering |
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