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28 Jan 2007 17:18:18 IST

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797

solve it in easy way

Engineering Entrance , JEE Main , JEE Advanced , Mathematics , Algebra

1.the number of ways of distributing 6 identical appples ,8 identical bananas ,11 identical oranges between two boys so that each boy gets at least one fruit of each kind

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aakash_128

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Joined: 27 Jan 2007

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28 Jan 2007 19:38:37 IST

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There are 6 identical apples,8 identical bananas,and 11 identival oranges....

So total no of ways of distributing apples among 2 students is 6p2...

similarly for bananas and oranges the total no of ways is 8p2 and 11p2 respectively...

So total no of ways of distributing it amongst the 2 persons is...

6p2+8p2+11p2..

Now by formulaof permutation NpR=N!/(N-R)!

calculate each..

and find the answer..

by the way please answer my question...

it seems that you are in 11th std...

if you have any further problem please mail me at aakashaastha@rediffmail.com.

Thank you..

vaibhavbright

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29 Jan 2007 20:56:39 IST

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The ans is 25! / 6! 8! 11! - 2

vaibhavbright

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29 Jan 2007 20:56:57 IST

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The ans is 25! / 6! 8! 11! - 2

deepak_agarwal

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31 Jan 2007 09:31:16 IST

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(2^6)(2^8)(2^11)-(2^6-2^8-2^11)-(2^6)(2^8)-(2^8)(2^11)-(2^11)(2^6)........

see what i have done is total number of ways of distributing - ways of distributing so that none gets all the fruits

each fruit can go to either of the 2 boys...so 2^n is ways of distributing n fruits among 2 boyz......think over it and llet me know any sort of prob

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