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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Aug 2007 10:49:49 IST
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solve log1/3(x2-3x+5)<-1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Aug 2007 10:54:21 IST
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therefore... x^2-3x+5>(1/3)^(-1) (sign will change......!!!!!!!!!!!!!)
so as (1/3)^-1 = 3, x^2-3x+2>0
(x-1)(x-2)>0
x (- ,1)U(2, )............
HOPE U GOT IT .........!!!!!!!!!!!!!!!!!!!
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Aug 2007 11:22:40 IST
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c wen (x-a)(x-b)>0, then x belongs 2 (- ,a)U(b, )...................!!!!!!!!!!!! assuming tht a<b........!!!!!!!!!!!!!!!!!!
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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