IIT JEE , AIEEE Forum - Mathematics , Algebra

dixit_se

find the number of ordered pairs(x,y) satisfying x²+1=y and y²+1=x

nivedh_89

0 pairs .......................according 2 me....................!!!!!!!!!!!!!!!!!!!!!!!
bcas, whatever is the value of x, y will b greater than x in the first equation.........and in the 2nd it will b the opposite way.....tht is x>y............!!!!!!!!!!!!
hence i conclude tht there will b no real pairs of x n y.........!!!!!!!!!!!

spideyunlimited

draw the graphs of the 2 equations
x^2 = y-1
y^2 = x-1..
they dont intersect at any point
so 0 solutions

b_srikalyan009

the graphs of y=x²+1

and x=y²+1

they never intersect each other u can also solve by slope method

hence there are zero ordered pairs

karthik_karthik9920

xactly....no solution or u can even try traditional...substitution

plz...rate me!!!!!!!!1

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