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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Mar 2008 20:33:28 IST
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1 1+p 1+p+q 2 3+2p 1+3p+2q 3 6+3p 1+6p+3q
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in second row the last term is 1+3p+2p or 1+3p+2q check it
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Mar 2008 20:39:28 IST
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is the answer 1....................the above comment is right .........i hav answered it after correcting it
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Mar 2008 20:40:16 IST
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yes ur correct it is 2q
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Mar 2008 20:43:02 IST
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yes i 2 have got the answer 1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Mar 2008 20:47:24 IST
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the sol goes as:
1 1+p 1+p+q 2 3+2p 1+3p+2q 3 6+3p 1+6p+3q ------------------------ 1 1+p 1+p+q 1 2+p 2p+q 1 3+p 3p+q ------------------------ 1 1+p 1+p+q 0 1 -1+p 0 1 p ------------------------ xpand usiing 1st row (1*p)-(p-1)*1=p-p+1=1
plz... rate if find the answer correct
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Mar 2008 20:48:44 IST
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Im getting it as 1.. see,split it as | 1 1+p 1+p | | 1 1+p q | | 2 3+2p 1+3p | + | 2 3+2p 2q | | 3 6+3p 1+6p | | 3 6+3p 3q | and determinant is 0... in 1st determinant,do R3=R3-R1-R2...and then R2=R2-2R1 and then expanding along C1,you get 1st determinant as 1 So,final answer 1..
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