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Algebra

Cool goIITian

Joined:	9 Oct 2007
Post:	73

9 Oct 2007 01:15:15 IST

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314

Solve this question for all the set values of a.........Rates assured

None

IF xsquare -x + a < 0 for atleast one negetive value of x then complete set values of a is

options......

1) (-

,3)

2) (-

,4)

3)(-

,2)

4) (-

,1)

HEy if u solve i will surely rte..........Plz rate me for this wonderful question

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Comments (1)

Gaurav |spideyunlimited| Ragtah

Moderator

Joined: 16 Dec 2006

Posts: 3373

9 Oct 2007 20:41:02 IST

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YOUR QUESTION IS WRONG
for - ve value of x
x^2 - x will always be positive and then a's upper domain will be -ve and none of ur options correspond to that
plus it should be x^2 - x - a otherwise imaginary roots only exist.

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