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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Aug 2008 21:14:33 IST
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let n1 and n2 be natural nos., and n2= n1+2 . and n2<=1000
then when we multiply n1 and n2 which digit will occur the least time at unit digit.
a)4 b)9 c)0 d) both a and c
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19 Aug 2008 12:17:22 IST
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n1n2 = (n1+1)2-1 and the possible last digits are (0,3,4,5,8,9) of which 4 and 9 appear only once for numbers 1- 10. So (d) is right.
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19 Aug 2008 22:07:05 IST
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thnx
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