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Algebra
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Priyesh
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Joined: 18 Feb 2007
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26 Dec 2007 21:02:30 IST
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let the vertices be A(-1,2,1) B(1,-2,5) C(4,-7,8) & D(2,-3,4)
midpt of AC = (3/2,-5/2,9/2) (using midpt formula)
similarly
midpt of BD = (3/2,-5/2,9/2)
hence AC & BD bisect each other so the quadrilateral is a parelleogram with diagnals AC & BD
(using property that if in a quad. diagnals bisect each other it is a parellelogram)
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