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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Sum
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[Post New]27 Mar 2008 17:09:37 IST
    Subject: Sum
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pantpranav (367)

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Find the sum of the series:
53 + 4*63 + 73 + 4*83 + 93 + 4*103 + --------------------------------- n terms.

Ans- n(10n3 + 96n2 + 343n + 540)


    
[Post New]27 Mar 2008 17:39:05 IST
    Subject: Re:Sum
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sandeepramesh (1247)

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am i missings th? n=1 doesnt work?
 
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[Post New]27 Mar 2008 17:49:41 IST
    Subject: Re:Sum
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elastiboysai (2327)

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clearly the ans is wrong
anyway the method is


\Sigma_{r=2}^k(2r+1)^3+\Sigma_{r=2}^{k+1}4\cdot(2r+2)^3
u need 2 take care of values of k n k+1 as per n
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