IIT JEE , AIEEE Forum - Mathematics , Algebra - sum of 1/sqroot{2}+1/sqroot{3}+1/sqroot{4}+....+1/sqroot{10000}

ramkumar_november

go to this link :::

http://www.goiit.com/posts/list/algebra-solve-for-definite-salutes-32483.htm

RyuAmakusa

T_a = 1/ $\sqrt{a+1}$ now for all values of given 'a' T_n is less than 1 so the curve is very very....steep. so this sigma can be approximated as a integeral in other words

$\sum_{2}^{10000} Tn\approx \int_{2}^{10000} \frac{1}{\sqrt{x}}dx =2(\sqrt{x})]$

= 2(100-1.414) =197.172 but the actual value is 197.544645....u see they are almost =

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