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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Aug 2008 19:56:34 IST
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Sum on Probability:::::::
The chance of a teacher to take a surprise test on a meet with his students is (1/5).A student remains absent for 2 consecutive meets.What is the probabilility that he will miss at least one test.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Aug 2008 19:58:57 IST
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where is the Q...
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IMPOSSIBLES ARE OFTEN UNTRIED... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Aug 2008 20:40:52 IST
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1/5*4/5 + 4/5*1/5 + 1/5*1/5 = 8/25 + 1/25 = 9/25
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Aug 2008 21:00:19 IST
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Can u plz tell me the logic.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Aug 2008 21:10:19 IST
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prob. of missing at least one test = prob. of missing 1 test + prob. of missing both tests = (test)(no test) + (no test)(test) + (test)(test) = 1/5*4/5 + 4/5*1/5 + 1/5*1/5
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- Gaurav Ragtah (spideyunlimited)
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