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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2008 21:02:18 IST
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3.nC0 - 8.nC1 + 13.nC2 - 18.nC3 + .......upto (n+1)
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Caution: Radioactive Hazard |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2008 21:18:31 IST
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is the answer zero
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2008 21:30:59 IST
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Yes answer should be zero
Express it in the general term ,
T r = (-1) r (3 + 5r) n Cr is the general term of an A.P
So put r = 0,1,2,3......n
S = r = 0 n (-1) r (3 + 5r) n Cr = (-1) r 3 n C r + 5 (-1) r r . nCr = 3 (-1) r n C r + 5 (-1) r . r n C r
= 0
Problem 80 , Pg A-199 A.Daspupta 
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2008 21:52:19 IST
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yep i solved it like that!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Mar 2008 15:02:43 IST
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answer is 0 since when series is in an ap with consecutive - sign sum adds 2 zero
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