Given : tk=k(k!),
Then
= Sn = 1.1! + 2.2! + 3.3! + ................. + n.n!
Let : Vn = ( n + 1 )!
So: Vn -1 = n!
Vn - Vn -1 = (n + 1)! - n! = n.n! = Tn
Vn -1 - Vn -2 = n! - (n - 1)! = (n - 1).(n - 1)! = Tn -1
.
.
V1 - V0 = 2! - 1! = 1.1! = T1
Therefore: Sn = T1 + T2 + T3 + ......... + Tn
= Vn - V0
= (n + 1)! - 1