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Ask iit jee aieee pet cbse icse state board experts Expert Question: summation of n factorial
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umang_rathi777 (5)

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solve this summation of n factorial
[ 0][n ]n!
    

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ankur.kkhurana (922)

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(n+1)!/n -1

adversities cause some men to break other to break records............i m of the other type....... :-)
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fatafati (14)

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That's incorrect answer. Check by taking different values of n.
But nice attempt !!

Believe in yourself so you that you can believe in others.
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sachin_batwani (0)

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Its (n+1)! - 1!
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umang_rathi777 (5)

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i am sorry but i also dont know answer
if any 1 gives answer plz justify it
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konichiwa2x (2388)

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The sum-of-factorials function is defined by
S_1(n) = sum_(k==1)^(n)k!
 
= (-e+Ei(1)+pii+E_(n+2)(-1)Gamma(n+2))/e
 
= (-e+Ei(1)+R[E_(n+2)(-1)]Gamma(n+2))/e,
where Ei(z) is the exponential integral. Ei(1) approx 1.89512 E_n is the En Function, R[z] is the real part of z, and i is the imaginary number. The first few values are 1, 3, 9, 33, 153, 873, 5913, 46233, 409113, ...
 
but why do you need this? I am sure no problem of IIT level would require you to remember the above formula.

Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm

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ankur.kkhurana (922)

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my answer may be wrong but method is correct
do you know about putting first and last value by breaking terms

well if you i can explain

adversities cause some men to break other to break records............i m of the other type....... :-)
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iitkgp_bipin (6544)

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konichiwa2x has already writen the expression for the sum of factorials.
If you want to gain knowedge on this topic you can refer to the link :
 
 
@ sachin_batwani,  the summation of (r).(r!) gives (n+1)! - 1  and not of r!.
 
Best Wishes

Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

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