| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Apr 2007 22:25:20 IST
|
|
|
1+1/3+1/5+1/7+1/9+1/11+......inf pls ans
|
|
|
All India Online Test on 25th Jan 2009 for - IIT, AIEEE, KCET, EAMCET and many more .. |
| Enrol Free. Refer Friends. Win I-Phone 3G.
Register Now for FREE» |
|
|
14 Apr 2007 22:48:53 IST
|
|
|
Always think about to make general term of any series and then try to solve it some way. In this case, the general term is Tn = 1/(2n+1) Then find  [Tn] by using partial fraction solve it . If the word "Infinity" is your problem then find limit as a sum.
|
Sometimes, its better to see behind ourselves to enlighten our forward direction. |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
All India Online Test on 25th Jan 2009 for - IIT, AIEEE, KCET, EAMCET and many more .. |
| Enrol Free. Refer Friends. Win I-Phone 3G.
Register Now for FREE» |
|
|
14 Apr 2007 22:57:29 IST
|
|
|
i am not able to solve the summation can u help me pleaseee
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
All India Online Test on 25th Jan 2009 for - IIT, AIEEE, KCET, EAMCET and many more .. |
| Enrol Free. Refer Friends. Win I-Phone 3G.
Register Now for FREE» |
|
|
14 Apr 2007 23:07:09 IST
|
|
|
how can it be solved by limit as sum as upper lim is infinity so
h=b-a/n=inf-a/n
|
this reply: 2 points
(with 0
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
All India Online Test on 25th Jan 2009 for - IIT, AIEEE, KCET, EAMCET and many more .. |
| Enrol Free. Refer Friends. Win I-Phone 3G.
Register Now for FREE» |
|
|
|
|
|
|
i you observe the series it happens to be in harmonic progressions and SUCH A SERIES CAN NOT BE SUMMED.
i.e. there happens to be no general formula to find the sum of this.
rate me for the info...
|
IIT- Imposible Is This(atleast fr meeeeeeeee) |
this reply: 2 points
(with 0
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
All India Online Test on 25th Jan 2009 for - IIT, AIEEE, KCET, EAMCET and many more .. |
| Enrol Free. Refer Friends. Win I-Phone 3G.
Register Now for FREE» |
|
|
15 Apr 2007 14:04:59 IST
|
|
|
try to solve it using logarithmic series
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
All India Online Test on 25th Jan 2009 for - IIT, AIEEE, KCET, EAMCET and many more .. |
| Enrol Free. Refer Friends. Win I-Phone 3G.
Register Now for FREE» |
|
|
16 Apr 2007 10:06:32 IST
|
|
|
how we can use log series
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
All India Online Test on 25th Jan 2009 for - IIT, AIEEE, KCET, EAMCET and many more .. |
| Enrol Free. Refer Friends. Win I-Phone 3G.
Register Now for FREE» |
|
|
16 Apr 2007 10:58:51 IST
|
|
|
Do u know how to use binomial theorem of infinite series. May it help u. Becoz I have no more Idea about this. You have a good question!!!
|
Sometimes, its better to see behind ourselves to enlighten our forward direction. |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
All India Online Test on 25th Jan 2009 for - IIT, AIEEE, KCET, EAMCET and many more .. |
| Enrol Free. Refer Friends. Win I-Phone 3G.
Register Now for FREE» |
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
