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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Jun 2008 20:13:40 IST
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tan (sin-1 3/5 +cot-1 3/2 ). find value where -1 stand for inverse
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2 Jun 2008 20:18:23 IST
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tan( 6/17)
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IMPOSSIBLES ARE OFTEN UNTRIED... |
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2 Jun 2008 20:24:02 IST
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= tan (tan-1 3/4 + tan-1 2/3 )
using; tan-1a + tan-1 b = tan-1 a+b/1-ab ...... for ab<1
the exp reduces to, tan ( tan-1 3/4 + 2/3 / 1-6/12 )
= tan (tan-1 17/12 / 1/2 )
= tan(tan-1 17/6)
= 17/6
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