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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Jul 2008 23:46:49 IST
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The least integral value of a for which the equation
x2-2(a-1)x+(2a+1)=0 has both the roots positive , is
METHOD: D>=0 , sum of the roots>0 and f(0)>0
now i want to know that why the author has written f(0)>0 ????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Jul 2008 07:41:54 IST
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Because f(0) = constant term = product of roots
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Time wounds all heels |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Jul 2008 08:43:58 IST
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coeff. of x^2 term is +ve implies parabola is upward opening and both roots are +ve. which means f(0) would be greater than 0. wait i m attaching the dia...correct me if i m wrong sir.....
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padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....
PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
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Shubham
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jul 2008 00:56:08 IST
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how will we come to know that we have to impose the condition f(0)>0??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 Jul 2008 09:58:21 IST
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PRACTICE
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padhna likhna chad de mitra , nakal te rakhi aas , chak chaddar te so ja bhagta , Rabb karega tennu paas.....
PLZ NEVER EVER RATE ME FOR MY ANSWERS , IF U WANT TO COMPLIMENT ME THEN JUST BEAT UR HEAD & SAY
"YEH KIS PAGAL NE MERA QN. SOLVE KER DIYA"
I AM SERIOUS!!!!
EVEN SERIOUS ^ INFINITY
PLZZZZZZ NEVER RATE ME....HOPE U WILL UNDERSTAND....
Shubham
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